Q. 305.0( 5 Votes )
In Fig. 16.206, < A. 42°
B. 48°
C. 58°
D. 52°
Answer :
∠BDC = 42°
∠ABC = 90° (Angle in a semi-circle)
In 
ABC,
∠ABC + ∠BAC = 42° (Angles on the same segment)
90o + 42o + ∠ACB = 180°
∠ACB = 48°
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