If the medi

Sum of frequency = 40

f₁ + 5 + 9 + 12 + f₂ + 3 + 2 = 40

f₁ + f₂ = 9

l = lower limit of median class (30 – 40) = 30

n = number of observations = 31 + f₁ + f₂

cf = cumulative frequency of class preceding to the median

class = 14 + f₁

f = frequency of the median class = 12

h = class size = 10

2.5 × 1.2 = 20 – 14 - f₁

f₁ = 3

f₂ = 9 – 3

f₂  = 6

OR

n = number of observations = 100

n/2 = 50

CF of median class = 56

l = lower limit of median class (25 – 30) = 25

cf = cumulative frequency of class preceding the median class = 31

f = frequency of the median class = 25

h = class size = 5

Median = 28.8