Q. 305.0( 1 Vote )

# If <img sty

A = |A| = 2(0) + 3(– 2) + 5(1)

= – 1

Now, the cofactors of A

C11 = (– 1)1 + 1 – 4 + 4 = 0

C21 = (– 1)2 + 1 6 – 5 = – 1

C31 = (– 1)3 + 1 12 – 10 = 2

C12 = (– 1)1 + 2 – 6 + 4 = 2

C22 = (– 1)2 + 1 – 4 – 5 = – 9

C32 = (– 1)3 + 1 – 8 – 15 = 23

C13 = (– 1)1 + 2 3 – 2 = 1

C23 = (– 1)2 + 1 2 + 3 = – 5

C33 = (– 1)3 + 1 4 + 9 = 13

adj A = A – 1 = A – 1 = A – 1 = Now the given equation can be written as: A X B

Or, X = A – 1B

=  X = Hence, x = 1,y = 2 and z = 3

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