Q. 304.5( 13 Votes )
If A, B and C are interior angles of a triangle ABC, then
=.
A. sin A/2
B. cos A/2
C. –sin A/2
D. -cos A/2
Answer :
Given,
A, B and C are the interior angles of ∆ ABC,
Therefore,
A + B + C = 180°
B + C = 180° - A
Now put this value in the given equation we get,
[∵ sin (90 – θ) = cos θ]
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