Q. 304.5( 13 Votes )

# If A, B and C are interior angles of a triangle ABC, then =.A. sin A/2B. cos A/2C. –sin A/2D. -cos A/2

Given,

A, B and C are the interior angles of ∆ ABC,

Therefore,

A + B + C = 180°

B + C = 180° - A

Now put this value in the given equation we get,

[ sin (90 – θ) = cos θ]

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Smart Revision | Trigonometric Ratios41 mins
Quiz | Task on Trigonometric Ratios46 mins
NCERT I Trigonometric Ratios50 mins
Basic Concepts of Trigonometry45 mins
Trigonometric Identities33 mins
Quiz on Trigonometric Ratios31 mins
Champ Quiz | Trigonometric Identities33 mins
Applying the Trigonometric Identities52 mins
Smart Revision | Trigonometric Identities40 mins
NCERT | Trigonometric Identities52 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses