Answer :

Let the height of the tower, PQ = h

Let the distance, BQ = x

In right ΔPQB, we have

x = h …(i)

In right ΔPQA, we have

[from (i)]

√3h = 20 + h

√3h – h = 20

h(√3 – 1) = 20

h = 10(√3 + 1)m

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