Answer :


Let the height of the tower, PQ = h


Let the distance, BQ = x


In right ΔPQB, we have




x = h …(i)


In right ΔPQA, we have




[from (i)]


√3h = 20 + h


√3h – h = 20


h(√3 – 1) = 20







h = 10(√3 + 1)m


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