Q. 34.3( 23 Votes )

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Answer :

Steps of Construction:

1. We draw a triangle ABC of given dimensions.

2. We draw a perpendicular bisector of side AB which intersects AC at D.

3. Join B to D.

4. Draw a line parallel to AC through B by completing the parallelogram AQBC.

5. From D, construct ∠GDA=60°.

6. The line cuts parallel line through B at E.

7. From E, cut an arc of length DA on the parallel line.

8. Mark the point as F.

9. Join F to A.

10. ADEF is the required parallelogram.

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<span lang="EN-USWest Bengal Mathematics

<span lang="EN-USWest Bengal Mathematics

<span lang="EN-USWest Bengal Mathematics

<span lang="EN-USWest Bengal Mathematics

<span lang="EN-USWest Bengal Mathematics

<span lang="EN-USWest Bengal Mathematics

<span lang="EN-USWest Bengal Mathematics

Pritam drew a quaWest Bengal Mathematics

<span lang="EN-USWest Bengal Mathematics

<span lang="EN-USWest Bengal Mathematics