# Two poles of height 6 m and 11 m stand vertically upright on a plane ground. If the distance between their feet is 12 m then the distance between their tops isA. 12 mB. 13 mC. 14 mD. 15 m

Given: Height of pole 1 = 6 m

Height of pole 2 = 11 m

Distance between the feet of pole 1 and pole 2 = 12 m

To find: Distance between the tops of both the poles

DE = 5 m

Also, ADE = 90° [ Both the poles stand vertically upright]

By applying Pythagoras theorem, we have

AE2 = (12)2 + (5)2 = 144 + 25 = 169

AE = √169 = 13 m

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