Q. 3

# The point on x-axis which is equidistant from points A(-1, 0) and B(5, 0) isA. (0, 2)B. (2, 0)C. (3, 0)D. (0, 3)

For the point to be equidistant, the point has to be the midpoint of the line joining the points A and B.

If P(x, y) is the midpoint of the line joining AB then By Midpoint Formula we have, and y Finding x co-ordinate of midpoint:  x = 2

Finding y- co-ordinate of midpoint: y = 0

Therefore the point which is equidistant from A and B is P(2,0).

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