# The hypoten

Let the base be ‘x’ and perpendicular be ‘y’.

Area of triangle    15 = xy … (1)

By Pythagoras Theorem,

(Base)2 + (Height)2 = (hypotenuse)2           … (2)

From equation (1),  2(x2 + 15) = 17 × x

2x2 + 30 = 17x

2x2 – 17x + 30 = 0

2x2 – 12x - 5x + 30 = 0

2x (x – 6) – 5(x – 6) = 0

(2x – 5) (x – 6) = 0

2x – 5 = 0 or x – 6 = 0

2x = 5 or x = 6 or x = 6

Put in equation (2)   Put x = 6 in equation 2   Base of triangle can be or 6

Perpendicular of triangle can be or 6.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos  Equations of Motion41 mins  Master the Art of Writing Chemical Formulae42 mins  Combinations of Solids43 mins  Law of Gravitation40 mins  Newton's Second Law46 mins  Master Mole Concept in 45 Minutes48 mins  Quick Recap of Cell62 mins  Circles- All kinds of Questions36 mins  Arc of Circle And Related IMP Qs40 mins  Surface Area and Volume of solids Revision43 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses RELATED QUESTIONS :

If the length of Kerala Board Mathematics Part-1

Four times a numbKerala Board Mathematics Part-1

Raju bought sevenKerala Board Mathematics Part-1

A 10-metre-long rKerala Board Mathematics Part-1

The length of a rKerala Board Mathematics Part-1

The sum of the diKerala Board Mathematics Part-1

The hypotenKerala Board Mathematics Part-1

Four years ago, RKerala Board Mathematics Part-1