The hypoten

Let the base be ‘x’ and perpendicular be ‘y’.

Area of triangle

15 = xy … (1)

By Pythagoras Theorem,

(Base)2 + (Height)2 = (hypotenuse)2

… (2)

From equation (1),

2(x2 + 15) = 17 × x

2x2 + 30 = 17x

2x2 – 17x + 30 = 0

2x2 – 12x - 5x + 30 = 0

2x (x – 6) – 5(x – 6) = 0

(2x – 5) (x – 6) = 0

2x – 5 = 0 or x – 6 = 0

2x = 5 or x = 6

or x = 6

Put in equation (2)

Put x = 6 in equation 2

Base of triangle can be or 6

Perpendicular of triangle can be or 6.

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