Answer :

Let the base be ‘x’ and perpendicular be ‘y’.


Area of triangle





15 = xy … (1)


By Pythagoras Theorem,


(Base)2 + (Height)2 = (hypotenuse)2












… (2)


From equation (1),




2(x2 + 15) = 17 × x


2x2 + 30 = 17x


2x2 – 17x + 30 = 0


2x2 – 12x - 5x + 30 = 0


2x (x – 6) – 5(x – 6) = 0


(2x – 5) (x – 6) = 0


2x – 5 = 0 or x – 6 = 0


2x = 5 or x = 6


or x = 6


Put in equation (2)





Put x = 6 in equation 2





Base of triangle can be or 6


Perpendicular of triangle can be or 6.


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