Answer :
We will prove by negation
i.e. If ABCD is a cyclic parallelogram then it is a rectangle
Proof:
∠ A + ∠ C = 180° (ABCD is a cyclic quadrilateral) …(1)
Since ∠ A = ∠ C (Opposite angles of a parallelogram) …(2)
⇒ ∠ A + ∠ A = 180° (from (1) and (2))
⇒ 2∠ A = 180°
⇒ ∠ A = 90°
Thus, ABCD is a rectangle.
That is a parallelogram which is not a rectangle is not cyclic.
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