Q. 34.0( 15 Votes )

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Answer :


Given that the trapezium is isosceles. Therefore from the fig. it is clear that SM = NR = 3cm


Also, PQ = MN = 7cm


Now, length of side SR = 3 + 7 + 3 = 13cm


Therefore, the sum of parallel sides of trapezium = 7 + 13 = 20


And the distance between them = 4 cm




= 40 sq cm


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