Answer :

Let in Δ ABC,

A = 60°


It is given that triangle is a isosceles triangle.


Case 1


Two equal angles both equal to 60°


If it happens, then sum of two equal angles will be = 60 + 60 = 120°


But, sum of all angles of a triangle is 180°


Thus, the third angle = 180-120 = 60


Hence, other two angles are 60° each.


Case 2


Two equal angles other than given angle (A)


If A = 60°


Let B = C = y°


Sum of all angles of a triangle is 180°


A + B + C = 180°


60 + y + y = 180°


60 + 2y = 180°


2y = 180-60


= 120



Hence the other 2 angles are also 60°


Hence, in both the cases the triangle is equilateral (each angle = 60°)


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