Answer :

Let us first construct what Megha had drawn


ABC = 60° only using scale and compass


Step1: Draw a ray BC. Take any distance in compass keep the needle of compass on point B mark an arc intersecting BC at X



Step2: Keeping the same distance in compass as that in step1 keep the needle on point X and mark an arc intersecting the arc drawn in step1 at Y. Draw ray AB passing though Y ABC = 60° is ready



Now the quadrilateral part


Step3: Take any points P and Q on BA and BC respectively



Constructing a line parallel to BC passing through P


Step4: Take the same distance in compass as that of in step1. Keep the needle on point P and mark an arc intersecting PA at M



Step5: Take distance XY in compass keep the needle of compass on point M and draw an arc intersecting arc drawn in step4 at N. Draw line passing through PN



Constructing a line parallel to BA passing through Q


Step6: Take the same distance in compass as that of in step1. Keep the needle on point Q and mark an arc intersecting QC at R



Step7: Take distance XY in compass keep the needle of compass on point R and draw an arc intersecting arc drawn in step6 at S. Draw line passing through QS which intersects line PN at D



From figure we have constructed


PD || BQ and BP || QD opposite sides of quadrilateral PBQD are parallel hence PBQD is a parallelogram


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