# <span lang="EN-US

Given, AB = QR

BC = PQ

CA = RP, which are corresponding sides of both triangles.

Thus, angles between any two of the corresponding sides in the two figures are matching angles.

Finding matching angles will help us to compute the remaining angles.

Therefore,

ABC = PQR = 70⁰

PRQ = CAB = 60⁰

Now, we have, In ∆ABC,

a + b + c = 180⁰

60⁰ + 70⁰ + c = 180⁰

130⁰ + c = 180⁰

c = 180⁰-130⁰

c = 50⁰

In ∆PQR,

p + q + r = 180⁰

p + 70⁰ + 60⁰ = 180

p + 130⁰ = 180⁰

p = 180⁰-130⁰

p = 50⁰

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses RELATED QUESTIONS :

<span lang="EN-USKerala Board Mathematics Part I

<span lang="EN-USKerala Board Mathematics Part I

<span lang="EN-USKerala Board Mathematics Part I

<span lang="EN-USKerala Board Mathematics Part I

<span lang="EN-USKerala Board Mathematics Part I

<span lang="EN-USKerala Board Mathematics Part I

<span lang="EN-USKerala Board Mathematics Part I

<span lang="EN-USKerala Board Mathematics Part I