Q. 34.5( 44 Votes )

In the given figu

Answer :

It is given that POQ = 110°


Since, the tangent at any point of a circle is perpendicular to the radius through the point of contact,


OPT = 90° and OQT = 90°


Now, in quadrilateral POQT,


POQ + OQT + PTQ + OPT = 360°


110° + 90° + PTQ + 90° = 360°


PTQ = 70°

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