Given G is the point of concurrence of medians of Δ DEF so the medians are divided in the ratio of 2:1 at the point of concurrence. Let O be the point of intersection of GH AND EF.
The figure is shown below:
⇒ DG = 2 GO
But DG = GH
⇒ 2 GO = GH
Also DO is the median for side EF.
⇒ EO = OF
Since the two diagonals bisects each other
⇒ GEHF is a ∥gram.
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