Q. 3 5.0( 1 Vote )

In Figure 2, AB and AC are tangents to the circle with center O such that BAC = 40°. Then calculate BOC.


Answer :

Given: AB and AC are tangents to the circle and BAC = 40°.


Since, AB and AC are tangents to the circle,



Therefore, OBA = ACO = 90°.


Since, ABOC is a quadrilateral, therefore sum of all angles of a quadrilateral is 360°.


BAC + ACO + BOC + OBA = 360°


BOC = 360° - BAC - ACO - OBA


= 360° - 40° - 90° - 90°


= 140°


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