# If the sum of n terms of an A.P. be 3n2 + n and its common difference is 6, then its first term isA. 2B. 3C. 1D. 4

Here, Sn= 3n2 + n

d = 6

Putting n= 1

S1 = 3 + 1 = 4

Sum of first 1 term = first term = 4

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