# If the length of

Given: Side of rhombus = 10 cm

Length of one diagonal = 12 cm

The figure for the question is:

We know that diagonals a rhombus are perpendicular bisector to each other.

So, the ΔAOB is a right angled triangles with AOB as right angle.

Now, in ΔAOB,

h = 10 cm

p = 6 cm

b = AO

By applying Pythagoras Theorem we have,

h2 = p2 + b2

102 = 62 + AO2

100 = 36 + AO2

AO2 = 100 – 36

AO2 = 64

AO = √64 = 8 cm

Also,

OD = AO = 1/2AD [ Diagonals of rhombus bisect each other]

Thus the length of the other diagonal is 16 cm.

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