Q. 33.8( 28 Votes )

<span lang="EN-US

Answer :

Put x = a throughout the polynomial

(a)3 + 2 × (a)2 –a + 10


p (a) = a3 + 2a2 – a + 10


Put x = -a throughout the polynomial


(-a)3 + 2 × (-a)2 –(-a) + 10


p (-a) = -a3 + 2a2 + a + 10


p(a) + p(-a):


a3 + 2a2 – a + 10 + -a3 + 2a2 + a + 10


p(a) + p(-a) = 4a2 + 20


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

Write the correctMHB - Math Part-I

Write the degree MHB - Math Part-I

Write the followiMHB - Math Part-I

Subtract the secoMHB - Math Part-I

Write the followiMHB - Math Part-I

Write the index fMHB - Math Part-I

Add the followingMHB - Math Part-I

Write the correctMHB - Math Part-I

Write the correctMHB - Math Part-I

Write the correctMHB - Math Part-I