Answer :
Given,
f(x) = x + 1
Therefore fof(x) = f[f(x)]
= f(x) + 1
= (x + 1) + 1
= x + 2
Differentiating with respect to x, we get,
As we know,
= 1x1-1 + 0x0-1
= 1 + 0
= 1
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