# Mark the correct alternative in each of the following:If f : A → B given by 3f(x) + 2–x = 4 is a bijection, thenA. A = {x ϵ R : –1 < x < ∞}, B = {x ϵ R : 2 < x < 4}B. A = {x ϵ R : –3 < x < ∞}, B = {x ϵ R : 0 < x < 4}C. A = {x ϵR : –2 < x < ∞}, B = {x ϵ R : 0 < x < 4}D. none of these

Given that f: A B given by 3f(x) + 2–x = 4 is a bijection.

3f(x) + 2–x = 4

3f(x) = 4 - 2–x

4 - 2–x ≥ 0

4 ≥ 2–x

2 ≥ -x

x ≥ -2

So, x ϵ (-2, ∞)

But, for x =0, f(x) = 1.

Hence, the correct option is none of these.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos  Functions - 0152 mins  Functions - 1047 mins  Functions - 0558 mins  Functions - 0748 mins  Functions - 0947 mins  Functions - 0253 mins  Functions - 0361 mins  Functions - 0840 mins  Functions - 1252 mins  Functions - 0460 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses 