Q. 35.0( 1 Vote )

# If a parallelogram has all its sides equal and one of its diagonal is equal to a side, show that its diagonals are in the ratio : 1. Given: ABCD is a parallelogram, where AC and BD are the diagonals meeting at O. AB = BC = AC.
To Prove: BD : AC :: : 1
Proof: In Δ ABC, AB = BC = CA (given).
= a (say)
Hence ABC is an equilateral triangle. (Definition of equilateral triangle)
AC and BD are the diagonals of parallelogram ABCD,
⇒ AC = BD (Diagonals of a parallelogram bisect each other)
or AO = OC.
i.e BO is the median of the equilateral ABC.
Hence BO = a
∴ BD = a
⇒ BD : AC :: a : a
⇒ BD : AC :: : 1.

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