# If and thenA. x = 2, y = 3B. x = – 2, y = 3C. x = 2, y = – 3D. x = – 2, y = – 3

We have,

…(i)

…(ii)

Now, multiplying (i) and (ii) by 6 we get:

4x – 3y = – 1 …(iii)

3x + 4y = 18 …(iv)

Now, multiplying (iii) by 4 and (iv) by 3 and adding them we get:

16x + 9x = – 4 + 54

Putting the value of x in (iv) we get:

3 × 2 + 4y = 18

y = 3

Hence, option A is correct

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