Q. 35.0( 1 Vote )

# Find a second deg

Given, p(1 + √3) = 0, p(1 – √3) = 0

Need to find a polynomial p(x) of second degree

since we know that p(1 + √3) = 0

if x = 1 + √3 is substituted in p(x) then it satisfies the equation

x – (1 + √3) = 0 , and ((x – 1) – √3) is one factor of p(x)

And p(1 – √3) = 0 is given

if x = 1 – √3 is substituted in p(x) then it satisfies the equation

x – (1 – √3) = 0, and ((x – 1) + √3) is one factor of p(x)

since, ((x – 1) – √3) and ((x – 1) + √3) are the factors of p(x), it can be written as follows

p(x) = ((x – 1) – √3)((x – 1) + √3)

p(x) = (x – 1 – √3)(x – 1 + √3)

p(x) = x2 – x + √3x –x + 1 – √3 – √3x + √3 – 3

p(x) = x2 – 2x – 2

x2 – 2x – 2 is the second degree polynomial which satisfies p(1 + √3) = 0 and p(1 – √3) = 0.

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