Q. 34.3( 16 Votes )
Construct Δ ABC, in which BC = 6cm, ∠ABC = 100° and AC – AB – 2.5CM
Given: Base BC = 6cm, AC-AB = 2.5cm and
∠B = 100° of Δ ABC.
Required: To construct a triangle ABC.
Steps of construction:
i: Draw a segment BC of length 6cm.
ii: Draw ray BT such that ∠B = 100°
iii: Mark an arc on opposite of ray BT i.e. ray BS cutting at D such that BD = 2.5cm.
iv: Draw segment CD.
v: Construct the perpendicular bisector of segment CD.
vi: Name the point of intersection of ray BS and the perpendicular bisector of CD as A.
vii: Draw segment AC.
ΔABC is the required triangle.
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