Q. 33.9( 20 Votes )
Construct Δ ABC, in which BC= 6.2cm, ∠C = 50°, AB+AC= 9.8cm
Given: base BC= 6.2cm,
AB+AC= 9.8cm and
∠C = 50° of Δ ABC.
Required: To construct a ΔABC
Steps of construction:
i: Draw a segment BC of length of 6.2cm.
ii: At vertex C, construct ∠C = 50° and produce a ray CP.
iii: Mark an arc on ray CP cutting at D such that CD = 9.8cm.
iv: Draw segment DB.
v: Construct the perpendicular bisector of segment DB.
vi: Name the point of intersection of ray CP and the perpendicular bisector of DB as A.
vii: Draw segment AB.
ΔABC is the required triangle.
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