Q. 33.9( 20 Votes )

Construct Δ ABC, in which BC= 6.2cm, C = 50°, AB+AC= 9.8cm

Answer :

Given: base BC= 6.2cm,

AB+AC= 9.8cm and


C = 50° of Δ ABC.


Required: To construct a ΔABC


Steps of construction:


i: Draw a segment BC of length of 6.2cm.



ii: At vertex C, construct C = 50° and produce a ray CP.



iii: Mark an arc on ray CP cutting at D such that CD = 9.8cm.



iv: Draw segment DB.



v: Construct the perpendicular bisector of segment DB.



vi: Name the point of intersection of ray CP and the perpendicular bisector of DB as A.



vii: Draw segment AB.



ΔABC is the required triangle.



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