Q. 35.0( 1 Vote )
Construct a tria
Step 1: Draw a line segment AB = 13 cm.
Step 2: Taking A as center, draw an arc of radius 5 cm. Then, take B as center and draw an arc of radius 12 cm. These arcs will intersect at point C (say). Join AC and BC, such that AC = 5 cm and BC = 12 cm. Thus, ∆ABC is the required triangle.
Step 3: Draw a ray AX making acute angle with straight line AB to the opposite side of vertex C.
Step 4: Locate 5 points on ray AX, namely A 1 , A 2 , A 3 , A 4 and A 5 (since 5 is greater among 3 and 5) such that, AA 1 = A 1 A 2 = A 2 A 3 = A 3 A 4 = A 4 A 5 .
Step 5: Join BA 5 and then draw a line through A 3 such that it is parallel to BA 5 and intersects on AB at B’.
Step 6: Now draw a line through B’ such that it is parallel to BC and intersects on AC at C’.
∆AB’C’ is the required triangle with sides 3/5 of the corresponding sides of ∆ABC.
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