Q. 2 J3.5( 14 Votes )

# Let’s resolve int

= (x + 1)(x-4)(x + 3)(x-6) + 24

= (x2-4x + x-4)(x2–6x + 3x-18) + 24

= (x2-3x-4)(x2–3x-18) + 24

Let x2 – 3x = a

= (a-4)(a-18) + 24

= a2-18a-4a + 72 + 24

= a2-22a + 96

= a2-16a-6a + 96

= a(a-16)-6(a-16)

= (a-6)(a-16)

Putting back the values of a we get,

= (x2 – 3x -6)( x2 – 3x -16)

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