Answer :

To resolve it into factors we first resolve 108

108=2×2×3×3×3


Given, x2 + (m + n)x + mn=(x + m)(x + n) … (2)


Comparing 1 and 2


m + n =31


mn =108


(1) can be written as


p2 + 27pq + 4pq + 108q2


= (p + 27q)( p + 4q)


The resolved factors are (p + 27q)( p + 4q)


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