Q. 2 E

# Let’s resolve into factors

x^{2}y^{2} + 23xy-420

Answer :

To resolve it into factors, we first factorize 420

420= 2×2×3×5×7

Given, x^{2} + (p + q)x + pq=(x + p)(x + q) … (2)

Comparing 1 and 2

p + q = 23

pq =-420

∴ (1) can be written as

x^{2}y^{2} + 35xy-12xy-420

= (xy + 35)(xy-12)

∴ The resolved factors are (xy + 35)(xy-12).

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