Answer :

(4a – 3)3 –(4a + 3)3 = [(4a)3 -{3 ×(4a)2 × 3 } + { 3 ×(4a)×(3)2 } -(3)3 ] - [(4a)3 +{3 × (4a)2 × 3 } +{3 ×(4a)×(3)2 } +(3)3 ]


{ (a + b)3 = a3 + 3a2b + 3ab2 + b3 and (a – b)3 = a3 –3a2b + 3ab2 – b3 }


= [ 64a3-{3 × 16a2 × 3 } +{3 × 4a × 9} - 27 ] – [ 64a3 +{3 × 16a2 × 3 } +{3 × 4a × 9} + 27 ]


= [ 64a3 - 144a2 + 108a -27 ] – [ 64a3 + 144a2 + 108a + 27 ]


= 64a3 - 144a2 + 108a – 27 – 64a3 - 144a2 - 108a - 27


= - 288a2 - 54


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