Q. 2 C5.0( 1 Vote )

# By comparing the

Answer :

5x + 8y = 14 …(1)

15x + 24y = 42 …(2)

Let us express the equations (1) and (2) in the form of

ax + by +c = 0 where a and b can’t be 0 at the same time.

[In the first equation, we use a_{1}, b_{1}, c_{1} and in second equation, we use a_{2}, b_{2}, c_{2} ]

5x + 8y = 14 15x + 24y = 42

∴ 5x + 8y – 14 = 0 ∴ 15x + 24y – 42 = 0

Or 5 × x + 8 × y + (-14) = 0 or, 15 × x + 24 × y + (-42) = 0

Here a_{1} = 5, b_{1} = 8, c_{1} = -14 and a_{2} = 15, b_{2} = 24, c_{2} = -42

Comparing the ratio of , we get

, and

Here . Therefore, it is solvable and has infinite common solutions. Lines will overlap.

Now, plot the lines on graph,

5x + 8y = 14 y = ... equation (i)

Equation (i) will be plotted as line AB.

15x + 24y = 42 y = ... equation (ii)

Equation (ii) will be plotted as line CD.

Here in the graph also, we can see that both lines are overlapped on each other. Therefore it has infinite common solutions.

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Let us solve the West Bengal Mathematics

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By comparing the West Bengal Mathematics

Let us solve the West Bengal Mathematics

Let us solve the West Bengal Mathematics

Let us solve the West Bengal Mathematics

Let us solve the West Bengal Mathematics

Let us solve the West Bengal Mathematics