Q. 2 B3.9( 14 Votes )

# Let’s resolve int

(x2-2x)2 + 5(x2-2x)-36

To resolve it into factors we first resolve 36

36=9×4

We know, x2 + (p + q)x + pq=(x + p)(x + q) … (2)

Comparing 1 and 2 we get,

p + q = 5

= 9 -4

pq = - 36

= 9 × (-4)

1 can be written as:

(x2-2x)2 + 9(x2-2x) - 4(x2-2x) -36

= (x2-2x)[ (x2-2x) + 9] – 4 [(x2-2x) + 9]

= (x2-2x +9) (x2-2x - 4)

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