Answer :

We have x^{2} + 7x + 10 = 0

Here, a (coefficient of x^{2}) = 1

b (coefficient of x) = 7

c (constant term) = 10

To factorize this equation, we have to find numbers p and q such that p + q = b and pq = c

i.e. pq = 10

the possible values for p & q are 2 & 5. Because (2 × 5 = 10) and (2 + 5 = 7)

X^{2} + 5x + 2x + 10 = 0

∴ x(x + 5) + 2(x + 5) = 0

∴ (x + 5)(x + 2) = 0

∴ x = -5 or x = -2

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