Q. 2 B4.0( 2 Votes )
In the multiplication table made earlier, take a square of nine numbers, instead of four, and mark the numbers at the four corners:
Explain using algebra, why this difference is the same for all such squares.
Answer :
we can write a row of multiplication table as
x 2x 3x 4x 5x 6x 7x 8x 9x
Next row will be:
(x+1) 2(x+1) 3(x+1) 4(x+1) 5(x+1) 6(x+1) 7(x+1) 8(x+1) 9(x+1)
If we take a general number from the first row as yx then the next number in this row will be (y+1)x.
So, we can obtain a general square of 9 terms from this multiplication table as:
Diagonal sums: (yx)+(y+2)(x+2) = yx+y(x+2)+2(x+2) = yx + yx + 2y +2x +4
= 2yx +2y +2x +4
Y(x+2)+ (y+2)x = (yx +2y)+(yx + 2x) = 2yx +2y +2x
Clearly, the difference between diagonal sums is equal to 4.
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