Q. 2 A4.0( 17 Votes )

# Factorize the fol

Put (x2 – x) = a

a2 – 8a + 12

a2 – 2a – 6a + 12

a (a-2) – 6(a-2)

(a-6) × (a-2)

but a = (x2 – x)

((x2 – x)-6) × ((x2 – x) – 2

(x2 – x -6) × (x2 – x -2)

(x2 –3x + 2x – 6) × (x2 – 2x + x -2)

(x (x-3) + 2(x – 3)) × (x(x-2) + 1(x-2))

(x + 2)(x-3)(x-2)(x+1)

Therefore, the factorized form = (x + 2)(x-3)(x-2)(x+1)

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