Answer :

Given: A.P 1, 7, 13, 19…


nth term of A.P is given by tn = a + (n – 1) × d


where,


a = first term of A.P = 1


d = common difference = 7 – 1 = 6


we have to find the 18th term hence n = 18


t18 = 1 + (18 – 1) × 6


t18 = 1 + 17 × 6


t18 = 1 + 102


t18 = 103


Therefore 18th term of the A.P 1, 7, 13, 19… is 103


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