Q. 2 A3.5( 2 Votes )

Take nine numbers forming a square in a calendar and mark the four numbers at the corners.



Add the squares of diagonal pairs and find the difference of the sums.

32 + 192 = 370

172 + 52 = 314

370 – 314 = 56

Do this for other such nine numbers.

Answer :

let the other numbers be


The squares of diagonal are


62 and 222


202 and 82


Add the squares of the diagonal pair


62 + 222


= 36+ 484


= 520


202 + 82


= 400+64


= 464


find the difference of these sums:


= 520 - 464


= 56


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