Q. 2 A5.0( 1 Vote )

# Take nine numbers forming a square in a calendar and mark the four numbers at the corners.

Add the squares of diagonal pairs and find the difference of the sums.

3^{2} + 19^{2} = 370

17^{2} + 5^{2} = 314

370 – 314 = 56

Do this for other such nine numbers.

Answer :

let the other numbers be

The squares of diagonal are

6^{2} and 22^{2}

20^{2} and 8^{2}

Add the squares of the diagonal pair

6^{2} + 22^{2}

= 36+ 484

= 520

20^{2} + 8^{2}

= 400+64

= 464

find the difference of these sums:

= 520 - 464

= 56

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