Q. 2 A5.0( 1 Vote )

# Take nine numbers forming a square in a calendar and mark the four numbers at the corners. Add the squares of diagonal pairs and find the difference of the sums.32 + 192 = 370172 + 52 = 314370 – 314 = 56Do this for other such nine numbers.

let the other numbers be The squares of diagonal are

62 and 222

202 and 82

Add the squares of the diagonal pair

62 + 222

= 36+ 484

= 520

202 + 82

= 400+64

= 464

find the difference of these sums:

= 520 - 464

= 56

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