Q. 294.5( 2 Votes )

Using the method

Answer :

The given lines are


5x – 2y - 10 = 0 y = (5x – 10)/ 2 … (1)


x + y – 9 = 0 y = 9 - x … (2)


2x – 5y - 4 = 0 y = (2x – 4)/ 5 … (3)


For line (1), table:



For line (2), table:



For line (3), table:



Drawing these lines (1), (2) and (3), we get the graph:



These lines intersect at A (2, 0), B (4, 5) and C (7, 2)


Area of ΔABC = area AMB + area BMNC – area ANC







= 21/2 sq. units.


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