Q. 294.0( 2 Votes )

Using factorization, find the roots of the quadratic equation: 4y^{ 2}+4y+1= 0.

Answer :

4y

^{ 2 }+ 4y + 1 = 0

4y

^{ 2 }+ 2y + 2y + 1 = 0

2y(2y

^{ }+ 1) + (2y + 1) = 0

(2y + 1)(2y

^{ }+ 1) = 0

(2y + 1) = 0 or (2y

^{ }+ 1) = 0

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