Q. 295.0( 3 Votes )
Two circles of sa A. 3/2
B. 2
C. 3
D. 1/4
Answer :
Given:
AO’ = r
O’P = r
PO = r
AO = AO’ + O’P + PO
⇒ AO = r + r + r
⇒ AO = 3r
Now,
Hence, AO: AO’ = 3
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