Q. 295.0( 1 Vote )

Mark the correct A. one-one and onto

B. many one and onto

C. one-one and into

D. many one and into

Answer :

Given that function f : R R defined by f(x) = 6x + 6|x|


Let f(x) = f(y)


6x + 6|x|=6y + 6|y|


Only when x = y


So, f is one-one.


Now for y=f(x)


y can never be negative which means for no x ϵ R y is negative.


So, f is not onto but into.

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