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Answer :

Given that function f : R R defined by f(x) = 6x + 6|x|

Let f(x) = f(y)

6x + 6|x|=6y + 6|y|

Only when x = y

So, f is one-one.

Now for y=f(x)

y can never be negative which means for no x ϵ R y is negative.

So, f is not onto but into.

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