Answer :
Given that function f : R → R defined by f(x) = 6x + 6|x|
Let f(x) = f(y)
⇒ 6x + 6|x|=6y + 6|y|
Only when x = y
So, f is one-one.
Now for y=f(x)
y can never be negative which means for no x ϵ R y is negative.
So, f is not onto but into.
Rate this question :
How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
view all courses
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation


RELATED QUESTIONS :
| Let * be a bina
Mathematics - Board PapersFind the id
Mathematics - Board PapersLet f : A →
Mathematics - ExemplarShow that the bin
Mathematics - Board PapersDetermine whether
RD Sharma - Volume 1Fill in the
Mathematics - Exemplar