Q. 295.0( 2 Votes )

Of all the closed

Answer :

Let r and h be the radius and height of the cylinder.



Given that, volume of cylinder = 128π cm3


We know that , V = πr2h


128π = πr2h



Let S be the Surface area of cylinder.


S = 2πr2 + 2πrh


S = 2π(r2+rh)





Now ,






r = 4


At r = 4,


Hence, for r = 4, surface area is minimum.


dimensions of the can for minimum surface area is r = 4cm and


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