# Of all the closed

Let r and h be the radius and height of the cylinder.

Given that, volume of cylinder = 128π cm3

We know that , V = πr2h

128π = πr2h

Let S be the Surface area of cylinder.

S = 2πr2 + 2πrh

S = 2π(r2+rh)

Now ,

r = 4

At r = 4,

Hence, for r = 4, surface area is minimum.

dimensions of the can for minimum surface area is r = 4cm and

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