# In Fig. 9.54, AB and CD are parallel lines and transversal EF intersects them at P and Q respectively. If ∠APR=25°, ∠RQC=30° and ∠CQF= 65°, then A. x = 55°, y = 40°B. x = 50°, y = 45°C. x = 60°, y = 35°D. x = 35°, y = 60°

Given,

AB CD

And, EF cuts them

So, 30o + 65o + PQR = 180o

95o + PQR = 180o

PQR = 85o

APQ + PQC = 180o (Co. interior angle)

25o + y + 85o + 30o = 180o

y = 40o

In PQR + PRQ + QPR = 180o

85o + x + y = 180o

x = 55o

Thus, x = 55o and y = 40o

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