Q. 295.0( 2 Votes )

# In ΔABC, it is given that AB = 9 cm, BC = 6 cm and CA = 7.5 cm. Also, ΔDEF is given such that EF = 8 cm and ΔDEF ~ ΔABC. Then, perimeter of ΔDEF is

A. 22.5 cm

B. 25 cm

C. 27 cm

D. 30 cm

Answer :

Perimeter of Δ ABC = AB + BC + CA

= 9 + 6 + 7.5

= 22.5 cm

Since the Δ ABC ∼ DEF

= (ratio of perimeter of triangles is equal to the ratio of the sides of the triangle )

=

=

= 30 cm

Rate this question :

The lengths of the diagonals of a rhombus are 24 cm and 10 cm. Find each side of the rhombus.

RD Sharma - MathematicsIn an isosceles triangle ABC, if AB = AC = 13 cm and the altitude from A on BC is 5 cm, find BC.

RD Sharma - MathematicsIn a , AB = BC = CA = 2 a and . Prove that

(i) (ii) Area () =

RD Sharma - MathematicsUsing Pythagoras theorem determine the length of AD in terms of b and c shown in Fig 4.219.

RD Sharma - Mathematics

If the sides of a triangle are 3 cm, 4 cm and 6 cm long, determine whether the triangle is a right-angled triangle.

RD Sharma - MathematicsAD is an altitude of an equilateral triangle ABC. On AD as base, another equilateral triangle ADE is constructed. Prove that Area () : Area () = 3 : 4.

RD Sharma - Mathematics