Q. 294.1( 7 Votes )

In a family of 3

Answer :

Let E be the event of having at least one boy

The probability that each child will be a boy is 1/2.


The probability that each child will be a girl is 1/2.


The probability of no boys = 1/2 × 1/2 × 1/2 = 1/8


Then, the number of favourable outcome is P(E) –P(not E)=1 where P(E) is probability of having at least one boy and P(not E) means the probability of having no boy at all.


Probability (at least 1 boy) = 1 - probability (no boys)= 1 - 1/8 = 7/8

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