Answer :

To find the area of the quadrilateral ABCD, we divide the quadrilateral into two triangles by joining A and C.

So, Area(ABCD) = Area(ΔABC) + Area(ΔACD)

Now,

Area(ΔABC) = [x1(y2-y3) + x2(y3-y1) + x3(y1-y2)]

= [(-4)(-4-(-5)) + (-3)(-5-8) + 0(8-(-4))]

= [(-4) × 1 + (-3) × (-13) + 0] = 35/2 = 17.5sq. units

Area(ΔACD) = [x1(y2-y3) + x2(y3-y1) + x3(y1-y2)]

= [(-4)(-5-6) + 0(6-8) + 5(8-(-5))]

= [44 + 0 + 65]

= [109] = 54.5 sq. units

Area(ABCD) = Area(ΔABC) + Area(ΔACD)

⇒ Area(ABCD) = 17.5 + 54.5 = 72sq.units

Rate this question :

How useful is this solution?

We strive to provide quality solutions. Please rate us to serve you better.

Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Expertsview all courses

Dedicated counsellor for each student

24X7 Doubt Resolution

Daily Report Card

Detailed Performance Evaluation