Q. 295.0( 1 Vote )

# Find the vector e

Answer :

The given points are A (3, –1, 2), B (5, 2, 4) and C (–1, –1, 6). Equation of any plane passing through A,

a(x-3)+b(y+1) + c(z-2) = 0

This plane passes through B and C as well so,

2a+3b+2c = 0 and

-4a+0b+4c =0

Solving these equations, we get,   Equation of the required plane,

3(x-3) -4(y+1) + 3(z-2) = 0

3x – 4y + 3z – 19 =0 ….(1)

In vector form, Now, distance of P(6, 5, 9) from (1),  Rate this question :

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